The ball does not fall in a straight line from A to B. It follows a parabolic path instead. Now, you may be nodding your head violently as if this were a too obvious statement, but you might also be feeling an urge to use that right triangle with a height of 10 and base of 5 to find some sort of angle. Whatever that angle is, it's certainly irrelevant to the problem at hand. |
With any projectile motion problem, it's good practice to separate everything into x and y components. I usually do this with two columns. I also choose point A to be the point (0,0).
x x0 = 0 m xf = 5 m v0x = ? |
y y0 = 0 m yf = -10 m v0y = 0 m/s ay = - 9.8 m/s2 |
![]() I like to use ay = - 9.8 m/s2 rather than using just 9.8 m/s2 and having to remember to place my negatives in later. It's a really good practice to take care of all your negative values prior to plugging them into an equation. That way, you never have to mess with the equations. |
Here's the equations that will see us through the remainder of the problem:
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The motion of an object moving solely under the influence of gravity near
the earth's surface is governed by ![]() |
All you need are these equations, which are really the same for both x and y with the difference being that ax = 0. All the worrying about negative signs should be done in the initial setup as we did above.
Now, plug in the values that were given. Since most of the known information is for the y-component, we'll start there.
The final part asked about the final velocity of the ball. To do this, we'll refer to the equations for the individual component velocities: